The dimensions of $(\mu_0 \varepsilon_0)^{-1/2}$ are

The magnetic moment has dimensions of

Dimensional formula for torque is

The dimensional formula for impulse is

The dimensional formula of a physical quantity is $[M^{a} L^{b} T^{c}]$. Then,that physical quantity is:

The position of a particle at time $t$ is given by the equation $x(t) = \frac{v_0}{A}(1 - e^{-At})$, where $v_0$ is a constant and $A > 0$. The dimensions of $v_0$ and $A$ respectively are: